WebMay 14, 2024 · With an LED bulb the concern would be the temperature of the control circuit in the bulb. The 660 watt rating of the lamp holder would indicate that should never be a concern, other parts of the lamp will always be the limiting factors. Unless the shade is ridiculously small, I would think a 60 W incandescent would be fine and 100 W probably ok. WebNo bulb will be fused Solution: Resistance of bulb having 100W and 250V ⇒ R1 = P V 2 ⇒ R1 = 100(250)2 = 625Ω Resistance of bulb having 200W and 250V ⇒ R2 = P V 2 = 200(250)2 = 2625Ω = 312.5Ω Since, both are connected in series. ∴ Req = 625+ 312.5 = 937.5 Therefore, current in the circuit when connected across 500∨ I = 937.5500
A 100W bulb \\ [ { {B}_ {1}}\\] and two 60 W bulbs \\
WebTwo electric bulbs 40W, 200 V and 100 W, 200V are connected in series. Then the maximum voltage that can be applied across the combination, without fusing either bulb is- (1) 280V (2) 400V (3) 3000V (4) 200 V Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions WebGE 32-Watt 48-in Medium Bi-pin (T8) 6500 K Natural Daylight Fluorescent Light Bulb (12-Pack). GE’s 32-Watt T8 Daylight Fluorescent bulbs provide very cool, bluish-white light. Their bluish-white light creates a very cool appearance. bottled water costco price
Two electric bulbs A and B rated 200 V ∼ 100 W and 200 V
WebFeb 18, 2024 · An electric bulb is marked 100W, 250V. What information does this convey? How much current will the bulb draw if connected to a 250V supply? electricity icse class-10 1 Answer +1 vote answered Feb 18, 2024 by Akul (72.5k points) selected Feb 18, 2024 by Vikash Kumar (i) Given 100W, 250V. ← Prev Question Next Question → … WebCorrect option is B) Resistance of 100Wbulb=200 2/100=400ohms Resistance of 60Wbulb=200 2/60=666.67ohms Resistance of 40Wbulb=200 2/40=1000ohms Therefore, total resistance in series = (400+666.67+1000)=2066.67ohms Current in the circuit = 200/2066.67=0.0967A WebMay 8, 2024 · A 100 W bulb B1 and two 60 W bulbs B2 and B3 are connected to a 250 V source as shown in figure. Now W1, W2 and W3 are the output powers of the bulbs B1, B2 and B3 respectively. Then (a) W1 … bottled water delivered to home